Q.6. In the figure, the radii of the two concentric circles are 17 cm and 10 cm. A line PQRS cuts the larger circle at P and S and the smaller circle at Q and R. If QR = 12 cm, calculate PQ. (HOTS) (Marks: 5)
Hint: Draw OL ⊥ PS
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Answer:
Given OP = 17 cm and OR = OQ = 10 cm
QR = 12 cm (We have interpreted R=12 cm as QR=12cm)
To find PQ:
Drop OM perpendicular to QR.
Since perpendicular from center to chord bisects the chord
MQ = 6 cm
In triangle OMQ, MQ = 6 cm, OQ = 10cm
Using Pythagoras theorem
OM = square root (100 – 36)
= square root (64)
= 8
In triangle OMP, OM = 8 cm, OP = 17 cm
using Pythagoras theorem
PM = square root (289 – 64)
= square root (225)
= 15 cm
Clearly PQ = PM – QM
= 15 cm – 6 cm
= 9 cm
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