Question

Q. 6) In the given figure QO and RO are the bisectors of <Q and <R
respectively. If <QPR = 75º and <PQR = 56° , then find
<QOR and <ORQ.

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Answer 1

Answer:

<PRQ = 180 - (75 + 56)

=180 - 131

=49

there is given QO and RO are the bisectors of < Q and < R

so, <OQR = 56/2 = 28

and <ORQ = 49/2 = 24.5

and <QOR = 180 - (28 + 24.5)

=180 - 52.5

=127.5

Answer 2

Answer:

$\huge \: answer$

⟨PRQ =180-(75+56)

=>180-131

=>49

In the given Question there is given QO and RO are the bisectors of ⟨Q and ⟨R

So,⟨OQR=56/2=28

And ⟨OEQ =49/2=24.5

And ⟨QOR =180-(28+24.5)

=180-52.5

=127.5

Hope it helps!

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