Question

Q.6. Let ABC be a right triangle in which
AB = 6 cm, BC = 8 cm and ZB = 90°. BD is
the perpendicular from B on AC. The circle
through B, C, D is drawn. Construct the
tangents from A' to this circle.​

Answer 1

step of construction

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1. construct a right Triangle ABC ,such that AB= 6cm ,BC= 8cm and √ABC=90°
2. mark the mid-point of BC as O
3. join OA
4. with O as a center and OB radius . draw a circle which intersects the the side AC of ∆ABC at D.
5. join BD ,which cuts OA at M
6. with center M and radius MA - BM a circle intersecting the first circle at B and E .
7. join AB and AE

Thus AB and AE are the required tangents drawn from point A.