Q. 6) Number of unit cell in 4g of X (atomic mass =40) which crystallizes in bcc pattern is(NA= Avogadro no.)
0.1 NA
2x0.1 NA
0.1 NA/2
2x NA
All the above
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Answer:0.1NA/2
Explanation: In bcc unit cell there are 8 corners and 1 body centre
Rank= 8*(1/8)+1=2
Therefore in one bcc unit cell there are 2 atoms of X
No. of atoms in 40g X= NA
No. of atoms in 1g X= NA/40
No.of atom in 4g X= 4*NA/40=NA/10
2 atoms occupy 1 unit cell
1 atom occupies 1/2 unit cell
NA/10 atom occupies (1/2)*(NA/10)= 0.1NA/2
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