Question

Q.6) Reduce to the lowest term of 32/48​

Answer 1

Answer:

Find the GCD (or HCF) of numerator and denominator. GCD of 32 and 48 is 16.

32 ÷ 1648 ÷ 16.

Reduced fraction: 23. Therefore, 32/48 simplified to lowest terms is 2/3.

Answer 2

Answer:

The lowest term will be $\frac{2}{3} .$

Step-by-step explanation:

In context to questions asked

We have to reduce the given fraction to its lowest terms,

Given that,

$\frac{32}{48}$

For solving first we have to find the GCD of the numerator and denominator

GCD of $32$ and $48$ is $16$.

Divide both the numerator and denominator by the GCD ,

$=> \frac{32\div 16}{48\div 16}$

Reduced fraction:

$= \frac{2}{3}$

Therefore, $\frac{32}{48}$ simplified to lowest terms is $\frac{2}{3}$.