Question

Q. 6. The value of 'p'if x2 + (p-3)x+ p = 0 has real and equal roots is​

Answer 1

Step-by-step explanation:

GIVEN

x2 + (p - 3) x + p = 0

Here, A = 1, B = (p - 3), C = p

Since, the roots are real and equal, D = 0

B2 - 4ac = 0

(p - 3)2 - 4(1) (p) = 0

p2 + 9 - 6p - 4p = 0

p2 - 10p + 9 = 0

(p - 1)(p - 9) = 0

p = 1 or p = 9

Answer 2

Answer:

p = 1 or p = 9