Question

Q.6)The values of x; y:z are
z H2O
xH2 + y02
O A. x=1;y=1;z=1
O B. x=2;y=1; z=2
O C.x=2; y=2; z=2
O D.x=2; y=1; z=1​

Answer 1

Answer:

1.635×10−18Jatom−1

Solution :

lonisation Energy (lE)=E∝−E1=0−E1,E1=−lE=−1.312×106Jmol−1.

The ground state energy of hydrogen of hydrogen atom can be calculated by dividing E1 with Avogradro's number,

E1=−1.312×1066.022×1023=−2.18×10−18Jatom−1

The energy of first excited state (E2)=−2.18×10−18(22)Jatom−1=−5.45×10−19Jatom−1.

Energy required to cause excitation (ΔE)=E2−E1=(−0.545×10−18)−(−2.18×10−18)

1.635×10−18Jatom−1

Answer 2

Answer:

I think your 2nd option is correct