Q.6
w
A tap situated at a height of 10 m
leaks and the water drops fall at
regular intervals. When the first drop
reaches the ground, the 5th drop
is about to leave the tap, then the
separation between the second and
the third drops is
25/8 m
C
Answers
Given : A tap situated at a height of 10 m leaks and the water drops fall at regular intervals.
When the first drop reaches the ground, the 5th drop is about to leave the tap
To Find : separation between the second and the third drops
Solution:
Tap Height = 10 m
S = ut + (1/2)at²
u = 0
a = g = 10 m/s²
Time to reach ground = t sec
=> 10 = 0 + (1/2)(10)t²
=> t = √2 sec
1st dropped fallen at t = 0
5th drop fallen at t = √2 sec
Time Gap between each consecutive drop = √2/4 Sec
2nd drop fallen at √2/4 hence traveled for √2 - √2/4 = 3√2/4
3rd drop fallen at 2√2/4 = √2/2 Sec hence traveled for √2/2 Sec
Distance covered by 2nd drop
= (1/2)(10) (3√2/4 )²
= 45/8 m
Distance covered by 3rd drop
= (1/2)(10) (√2/2 )²
= 5/2 m
separation between the second and the third drops = 45/8 - 5/2
= 25/8 m
separation between the second and the third drops is 25/8 m
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