Question

Q 60. A GIRL OF MASS 60 kg, THE AREA OF HER ONE FOOT IS 0.004 sq. m AND AN ELEPHANT OF MASS 6000 kg HAS AREA OF ONE FOOT 0.20 sq.m. CALCULATE THE RATIO OF THEIR PRESSURE EXERTED ON GROUND, PRESSURE
OF GIRL: PRESSURE OF ELEPHANT. (g = 10 m per sq. cm)​

Answer 1

Answer:

Force,F=60kgwt=60×9.8N

=60×

10

98

=6×98N

Area under the foot (A) =180cm

2

10000

180

m

2

∴P=

A

F

=

180

6×98×10000

Pa=

3

98

×10

3

Pa

=32.6×10

3

Pa