Question

Q. 62 If a = b - 4; b=2e + 5 and c = - 2 then 2a + 3b - 4c = ? (1) 1 (2)-1 (3) +5 (4-5 15​

Answer 1

Answer:

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

Now, we can perform the subtraction,

∴ Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

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