Q-66. The value of sin 18°/cos 72° is:
(a) 1
(b) 0
(c)-1
(d) 1/2
Answers
Answered by
4
Answer:
MARK ME
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T 123
Answered by
3
Answer:B.0
Step-by-step explanation:
sin18°/cos 72° = sin (90° - 18°) /cos 72° = cos 72° /cos 72° = 1(ii) tan 26°/cot 64° = tan (90° - 36°)/cot 64° = cot 64°/cot 64° = 1(iii) cos 48° - sin 42° = cos (90° - 42°) - sin 42° = sin 42° - sin 42° = 0(iv) cosec 31° - sec 59° = cosec (90° - 59°) - sec 59° = sec 59° - sec 59° = 0
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