Math, asked by anitalondhe, 8 months ago

Q-66. The value of sin 18°/cos 72° is:
(a) 1
(b) 0
(c)-1
(d) 1/2​

Answers

Answered by vanshika200653
4

Answer:

MARK ME

B

R

A

I

N

L

E

I

E

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T 123

Answered by ankitphanzira
3

Answer:B.0

Step-by-step explanation:

sin18°/cos 72°    = sin (90° - 18°) /cos 72°     = cos 72° /cos 72° = 1(ii) tan 26°/cot 64°    = tan (90° - 36°)/cot 64°    = cot 64°/cot 64° = 1(iii) cos 48° - sin 42°      = cos (90° - 42°) - sin 42°      = sin 42° - sin 42° = 0(iv) cosec 31° - sec 59°     = cosec (90° - 59°) - sec 59°     = sec 59° - sec 59° = 0

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