Question

Q 68 Two infinitely long conductors XY and PQ have the same magnetic induction. The distance of a particular point 'A' from the conductors XY and PQ is 10cm and 15cm respectively. If the current flowing through the conductor PQ is 6A, then the current through the conductor XY is:

Ops: A. • ЗА

Ο 2A

Ⓒ4A​

Answer 1

4 A

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Answer 2

Answer:

The current through the conductor is 4A.

Explanation:

the magnetic field of an infinitely long current-carrying wire is

B=μoI/2πd

μo=permeability constant=4π×$10^{-7}$

I=current through the wire

d=distance from the wire

as per the question, both wires have the same magnetic field,

caseI:

for the wire XY

d=10cm=10×$10^{-2}$m

B=μo×I/2π×10×$10^{-2}$       (1)

case II:

for the wire PQ

d=15cm=15×$10^{-2}$m

B=μo×6/2π×15×$10^{-2}$.      (2)

by equating equations (1) and (2) we get:

I/10=6/15

I=6×10/15=4A

Thus, the current flowing through the conductor XY is 4A.