Question

Q.7 A father picks up his child at 3:30 PM
from school. One day child left at 2:30 pm
and started to walk at the speed of 6km/h
and met his father on the way and they
reach home 24 min. early. Find the speed of
father?
(a) 12 km/h
(b) 16 km/h
(c) 20 km/h
(d) 24 km/h​

Answer 1

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(d) 24 km/h

Step-by-step explanation:

100% correct answer

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Answer 2

The speed of father is 24 km/h (option d is the correct answer)

Given,

father picks up his child at 3:30 PM

from school

One day child left at 2:30 pm

The Speed of the child is 6km/h

they

reach home 24 min. early.

To Find,

Find the speed of father

Solution,

According to the question the speed of the child is 6km/h

let us assume that father picks his child 24/2 = 12 mins before 3:30 pm.

so, the total distance cover father is:

12 mins= distance covered by son in (60-12)= 48mins.

Now,

Let consider T = total time is taken by father

t= total time is taken by child

and,. S= speed of father

s= speed of child

We have to find the value of S = speed of father

Therefore, T/t= S/s

or, 12/48 = S/6

or, ¼= S/6

or, S= 24 km/h

Hence, The speed of father is 24 km/h

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