Q. 7. Find the value of k for which the point (-1,3) lies on the graph of the equation 2x - y + k
= 0
[Board Term II, KVS, 2016) (2).
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Given equation is 2x−y+k=0
Given point (−1,3)
Accoding to question the point lies on line
2(−1)−3+k=0
−2−3+k=0
k=5
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