Question

Q.7) Find the zeroes of quadratic polynomial and verify the relationship between the zeroes and coefficient P (x) = x 2+5x+6

Answer 1

Answer:

Ans:1&6

Step-by-step explanation:

x2+5x+6

can be written as x2-6x-1x+6

x(x-6)-1(x-6)

(x-6) (x-1)

x=6,x=1

there fore, 6&1 are roots of the equ/ation..

the sum of the roots =-b/a

so from the given equation ,

a=1,b=5,c=6.

-b/a=-5/1

product of the roots =c/a

=6/1

=6..

hope it will help you..

pls comment me.

Answer 2

Answer:

-5/1,6/1

Step-by-step explanation:

p(x)=x^2+5x+6=0

x^2+2x+3x+6=0

x(x+2)+3(x+2)=0

(x+3)(x+2)=0

x+3=0,x+2=0

x= -3, x= -2

The zeroes of x^2+5x+6 are -3,-2

1. The sum of zeroes= -3+(-2)

=-3- 2

= 5= -b/a

2. rhe product of zeroes= -3 x (-2)

=6 = c/a

Therefore , the relationship between the zeroes and coefficients is p(x)= x^2 +5x+6 are 5/1,6/1