Question

Q.7. If sec 0 + tan 0 = 7, then sec 0 - tan o is:

(a)1/7
(b) 7
(c) 6
(d) 49​

Answer 1

Answer:

scc0²-tan0²=1

(sec 0 + tan 0)(sec 0 - tan o) =1

(7)(sec 0 - tan o) =1

(sec 0 - tan o) =1/7

therefore option (a) is correct...

Answer 2

Answer:

option a

Step-by-step explanation:

tan²0 +1 = sec²0