Q.7. If sec 0 + tan 0 = 7, then sec 0 - tan o is:
(a)1/7
(b) 7
(c) 6
(d) 49
Answers
Answered by
0
Answer:
scc0²-tan0²=1
(sec 0 + tan 0)(sec 0 - tan o) =1
(7)(sec 0 - tan o) =1
(sec 0 - tan o) =1/7
therefore option (a) is correct...
Answered by
0
Answer:
option a
Step-by-step explanation:
tan²0 +1 = sec²0
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