Q.7 if x² + x + 6 = (x+2)(x+3) for all x, then value of "k" is:
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Given: x
2
+kx+6=(x+2)(x+3) for all values of x
To find the value of k
Sol: x
2
+kx+6=(x+2)(x+3)
⟹x
2
+kx+6=x(x+3)+2(x+3)
⟹x
2
+kx+6=x
2
+3x+2x+6
⟹x
2
+kx+6=x
2
+5x+6
Equating both sides in the above condition we get,
The value of k=5
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