Question

Q.7. In a house 11 bulbs are connected in parallel. Each bulb takes a current of 0.1
ampere from 220 volt power supply. Calculate the combined resistance of all
the bulbs and current in tlie leads,​

Answer 1

$\huge\mathcal \red{Given :}$

No of bulbs = 11

Current consumed by 1 bulb = 0.1 A

Voltage = 220 V

We know that, by Ohm's law,

$\large \mathbb{V = I \: R}$

$\large = > R = \frac{V}{ I}$

$\: \: \: \: \: \: \: \: = \frac{220}{0.1 \times11 }$

$\: \: \: \: \: \: = 200 \: ohms$

Therefore, the combined resistance = 200 ohms

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Answer 2

Answer:

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