Q.7 of 75
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A proton of mass' m' charge
'e' is released from rest in a
uniform electric field of
strength 'E'. The time taken
by it to travel a distance 'd' in
the field is
2de
V mE
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Answered by
1
Answer:
Force acting on proton =qE
Acceleration a=
m
qE
Given proton is initially at rest u=0
we know X=ut+
2
1
at
2
⇒d=
2
1
⋅
m
Eq
t
2
⇒t=
Eq
2md
⇒t=
Ee
2md
( q = e for a proton)
solution
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