Question

Q.7 of 75
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A proton of mass' m' charge
'e' is released from rest in a
uniform electric field of
strength 'E'. The time taken
by it to travel a distance 'd' in
the field is
2de
V mE​

Answer 1

Answer:

Force acting on proton =qE

Acceleration a=

m

qE

Given proton is initially at rest u=0

we know X=ut+

2

1

at

2

⇒d=

2

1

⋅

m

Eq

t

2

⇒t=

Eq

2md

⇒t=

Ee

2md

( q = e for a proton)

solution