Question

Q 7 ... pls help ...give all the explanation then i will mark ur ans brilliant​

Answer 1

42 m/s2

Explanation:

average acceleration= V2-V1/T2-T1=delta V/deltaT

V2=10+2×5^2=60m/s

V1=10+2×2^2 =18

T2=5s

T1=2s

hope this will help please mark this in brilliant

Answer 2

Given,

The velocity of a particle is (10 + 2t²) m/s

To determine,

The acceleration of the particle,

Solution :-

We know,

$\rm{Acceleration=\dfrac{dv}{dt} }$

Where,

dv is the change in velocity and dt is the change in time.

→ For t = 2s,

v₁ = 10 + 2(2)²

⇒v₁ = 10 + 8

⇒v₁ = 18 m/s

$\rule{80}2$

→ For t = 5s,

v₂ = 10 + 2(5)²

⇒v₂ = 10 + 50

⇒v₂ = 60 m/s

dv = v₂ - v₁

⇒dv = 60 - 18

◘ ⇒dv = 42 m/s

dt = 5s - 2s

◘ ⇒dt = 3s

Now,

$\rm{Acceleration=\dfrac{dv}{dt} }\\\\\rm{\hookrightarrow a=\dfrac{42}{3} }\\\\\boxed{\boxed{\rm{\hookrightarrow a=14\ m/s^2}}}}$

Therefore, the answer is (d) 14 m/s².