q. 7 solve kr dijiye
Answers
Answer:
Initial volume of solution :- 2 liter ( Water + HCl)
▪️Volume of water added :- 4 liter
▪️Initial Molarity ( M) = 6M
◾Solution :-
◾As Molarity
= \sf{\dfrac{No. \:of \: Moles \: of\: solution}{Volume \:of\: Solution \:(in\: \it{l})}}=
VolumeofSolution(inl)
No.ofMolesofsolution
◾Now as Initial Molarity was 6
\implies \it{\dfrac{No. \:of\: Moles\: of\: solution}{2} = 6 }⟹
2
No.ofMolesofsolution
=6
\implies \sf{ No.\: of\: moles \:= 2 \times 6}⟹No.ofmoles=2×6
\implies \bold{ No.\:of \:moles\: = 12}⟹No.ofmoles=12
◾Now as the No. of Moles if HCl present is 12 Moles
▪️Hence the final Molarity
\longrightarrow \it{\dfrac{No. \: of \: moles}{Final\: volume \:of \:solution}}⟶
Finalvolumeofsolution
No.ofmoles
\implies \dfrac{12}{(2+4)} = Final \: Molarity⟹
(2+4)
12
=FinalMolarity
\implies \dfrac{12}{6} = Final\: Molarity⟹
6
12
=FinalMolarity
→ Final Molarity = 2 M
Explanation:
I hope you understand.