Q.7.Write the formula of an oxo-anion of Manganese (Mn) in which it shows the oxidation state is equal to its group number.
(a) KMnOa
(b) MnO2
(c)MnO
(d) MnCl2
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Answer:
It shows that the oxidation of Mn in MnO4– is +7 which is equal to its group number which is 7.
Explanation:
The group number of Manganese (Mn) is 7. Therefore, the formula of an oxo-anion of manganese (Mn) in which it shows the oxidation state 7 is MnO4–. Oxidation state of Mn in MnO4– can be calculated as follows:
Mn + (-2 x 4) = –1
Mn – 8 = –1
Mn = –1 + 8
Mn = +7
It shows that the oxidation of Mn in MnO4– is +7 which is equal to its group number which is 7.
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Explanation:
the formula of an oxo-anion of Manganese (Mn) in which it shows the oxidation state is equal to its group number is (b) MnO2
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