Computer Science, asked by pimpalkarpreeti11, 5 months ago

Q.7.
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Answered by TheBrainlyKing1

${✪QUESTION✪:-</p><p>Find the Solution of the given condition</p><p></p><p>[tex]\sf\dfrac{dy}{dx} - 3y \: cot \: x = sin2x,y = 2 \: when \: x = \dfrac{\pi}{2}$

✪SOLUTION✪

•The given differential equation is a linear differential equation i.e, of the form $\displaystyle\sf\dfrac{dy}{dx}$ +Py=Q

P=-3cot x and Q=sin 2 x

Here,⠀

$\sf I.F.={ \sf e\:}^{ \displaystyle \sf\int \small P \: dx}={e}^{ \displaystyle \sf\int \small -3 \: cot \: x}$

⠀⠀

$\displaystyle \sf = {e}^{ - 3 \: log(sin \: x)} = {e}^{log(sin \: x) ^{ - 3} }$ =e

⠀⠀⠀⠀⠀⠀⠀⠀⠀ $\sf( Assuming\:0 < x < \pi)(Assuming0<x<π)$

⠀⠀

$\sf = {(sin \: x)}^{ - 3}$ =(sinx)

Hence,the solution of the given equation is given by

⠀⠀

$\displaystyle \sf y{(sin \: x)}^{ - 3} = \int {(sin \: x)}^{ - 3} cos \: x \: dx+Cy(sinx)$

= $\displaystyle\sf2\int {(sin \: x)}^{ - 2} cos \: x \: dx=2∫(sinx)$ ⠀

$\displaystyle \sf = \dfrac{2{(sin \: x)}^{ - 1} }{ - 1}$ + C=

⠀⠀ $\sf or \: y = - 2{(sin \: x)}^{3 - 1} + C \: {sin}^{3}xory=−2(sinx)$

⠀⠀ $\sf or \: y = - 2{(sin \: x)}^{2} + C \: {sin}^{3}$ x .....(1)

When $\sf x=\dfrac{\pi}{2},\:then\:y=2x$ =

⠀⠀

$\sf \therefore2 = - 2{ sin}^{2} \bigg( \dfrac{ \pi}{2}\bigg) + C \:{sin}^{3} \bigg( \dfrac{\pi}{2} \bigg)$ ⠀

$\implies \sf2$ = - 2 + C⟹2=−2+C

⠀⠀

$\implies \sf C=4⟹C=4</p><p></p><p>Hence the required solution is</p><p></p><p>[tex]\sf \: y = - 2{(sin \: x)}^{2} + 4{sin}^{3}$ x .......(from 1)Fire insurance policies provide payment for the loss of use of the property as a result of a fire or for additional living expenses necessitated by uninhabitable conditions, as well as damage to personal property and nearby structures}[/tex]

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Q.7.
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