Question

Q.8
A rod is in equilibrium as shown in figure. What can be the weight of this rod?
0.5 m
W
0.25 m
0.75 m
F = 100 N
1
201​

Answer 1

Answer:

200N

Explanation:

(F1)(r1)=(r2)(W)

(100)(0.50)=(W)(0.25)

50=0.25W

W=50/0.25

W=200N. (answer)