Question

Q. 8. Calculate the mass of iron in 10 kg of iron ore which
contains 80% of pure ferric oxide.
Hyd​

Answer 1

Answer:

2 kg

Explanation:

100-20

80

10into20/100

2kg

Answer 2

Explanation:

Ferric oxide = iron(III) oxide = Fe2O3

molar mass Fe2O3 = 159.69 g/mol

molar mass Fe = 55.845 g/mol

10 kg × 0.8 Fe2O3 = 80 kg Fe2O3

80 kg Fe2O3 × (1 mol Fe2O3/159.69 g Fe2O3) × (2 mol Fe/1 mol Fe2O3) × (55.845 g Fe/1 mol Fe) = 55.953 kg