Q.8 Commercially available conc. H2SO4 contains 93% by mass of H2SO4.What is the molarity of this solution?
(Given : at mass of H=1, S=32, 0=16, density of H2SO4 solution = 1.84 gm/ml.)
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The given H2SO4 is 98%by wt, hence
100g solution contains 98g H2SO4 by mass
now density d=(m/v) ∴v=(m/d)
here, d=1.84g/c.c. m=100g, v=?
∴v=(100/1.84)mL=
again molarity=
here weight taken W=98g, molecular weight of H2SO4 (M)=98g/mol,
volume (V)=
putting these values we get
∴molarity=(98*1.84*1000)/(98*100)=18.4(M)——Ans
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100g solution contains 98g H2SO4 by mass
now density d=(m/v) ∴v=(m/d)
here, d=1.84g/c.c. m=100g, v=?
∴v=(100/1.84)mL=
again molarity=
here weight taken W=98g, molecular weight of H2SO4 (M)=98g/mol,
volume (V)=
putting these values we get
∴molarity=(98*1.84*1000)/(98*100)=18.4(M)——Ans
This is your answer...
Thank you
Mark as branliest..
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