Question

Q#8
Determine the equivalent resistances across terminal pairs a-b of the networks shown in
Figure Q#8

Answer 1

The equivalent circuit is shown in figure.

here, R

eq1

=

10+10

10×10

=5Ω, R

eq2

=5+10=15Ω,

R

eq3

=

15+10

15×10

=6Ω

Thus, R

AB

=R∣∣(10+6)+10=

16+R

16R

+10

or 18=

16+R

16R

+10

or 8=

16+R

16R

or 16+R=2R⇒R=16Ω

Answer 2

Answer:

Q#7

(a) Find VX in the circuit shown in Figure Q#7a using KVL and Ohms law

(b) Find ix and v in the circuit shown in Figure Q#7b

(c) Calculate I0 and the voltage across the 10Ω resistor in Figure Q#7c