Question

Q.8) Divide 150 into three parts such that the second number is five-sixths of the first and third is fourth-fifths of second​

Answer 1

Let the 3 parts be a,b, and c

Given:First part:x

second part

6

5

of x is

6

5x

third part

5

4

0f second part=

5

4

×

6

5x

=

3

2x

sum of three parts is =150

⇒x+

6

5x

+

3

2x

=150

⇒6x+5x+4x=6×150

⇒15x=6×150

⇒x=6×

15

150

=60

three parts of 150 are respectively

First part=60

Second part=

6

5

×x=

6

5

×60=50

Third part=150−Sum of other two parts=150−(60+50)=40

∴The lengths are 60,50, and 40

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