Question

Q 8. Draw a line segment of length 10 cm and construct its
perpendicular bisector.
and compasses draw an angle of measure 45° and bisect it. Verify by​

Answer 1

Answer:

it is so easy draw line of 10 cm

Step-by-step explanation:

then make a 90degree angle and then bisect it

Answer 2

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answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)f(2)=16+12−18−10=0

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)f(2)=16+12−18−10=0So, by similar reasoning, (x−2) is also a factor of f(x)

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)f(2)=16+12−18−10=0So, by similar reasoning, (x−2) is also a factor of f(x)Therefore, f(x)=(x+1)(x−2)p(x)=(x2−x−2)p(x)

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)f(2)=16+12−18−10=0So, by similar reasoning, (x−2) is also a factor of f(x)Therefore, f(x)=(x+1)(x−2)p(x)=(x2−x−2)p(x)By synthetic division, we can find p(x)

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)f(2)=16+12−18−10=0So, by similar reasoning, (x−2) is also a factor of f(x)Therefore, f(x)=(x+1)(x−2)p(x)=(x2−x−2)p(x)By synthetic division, we can find p(x)⇒f(x)=2x3+3x2−9x−10=(x2−x−2)(2x+5)

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)f(2)=16+12−18−10=0So, by similar reasoning, (x−2) is also a factor of f(x)Therefore, f(x)=(x+1)(x−2)p(x)=(x2−x−2)p(x)By synthetic division, we can find p(x)⇒f(x)=2x3+3x2−9x−10=(x2−x−2)(2x+5)Therefore p(x)=2x+5 and the factorization of f(x) is 

answrJoin / LoginWhat would you like to ask?UntaggedUse Remainder theorem to factorize the following polynomial. 2x3+3x2−9x−10.Let f(x)=2x3+3x2−9x−10, then f(−1)=−2+3+9−10=0So, by remainder theorem, when f(x) is divided by x+1, the remainder is 0. So, (x+1) is a factor of f(x)f(2)=16+12−18−10=0So, by similar reasoning, (x−2) is also a factor of f(x)Therefore, f(x)=(x+1)(x−2)p(x)=(x2−x−2)p(x)By synthetic division, we can find p(x)⇒f(x)=2x3+3x2−9x−10=(x2−x−2)(2x+5)Therefore p(x)=2x+5 and the factorization of f(x) is f(x)=(x+