Question

Q. 8. Expand (x^3+2y^2)^3​

Answer 1

Answer:

We take a=x,b=2y,c=3z in the expansion

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca

We obtain

(x+2y+3z)2=x2+(2y)2+(3z)2+2x(2y)+2(2y)(3z)+2(3z)x=x2+4y2+9z2+4xy+12yz+6zx