Q-8-Express
i/1-i
in the form of a +ib
Answers
Answer:
1/1-i Rationalise it
1/1-i×1+i/1+i
1+i/1-i^2
1+i/1+1
1+i/2 i^2 =-1,so-i^2 =1
1/2 + i/2
real part=1/2
imaginary part=i/2
Answer:
Answer:1-i/-2
Answer:1-i/-2Step-by-step explanation:
Answer:1-i/-2Step-by-step explanation:i/1-i
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it,
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-i
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2i
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2i
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2iRationalise it again because we can't leave iota in denominator
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2iRationalise it again because we can't leave iota in denominator i+1/-2i × - 2i/-2i
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2iRationalise it again because we can't leave iota in denominator i+1/-2i × - 2i/-2i-2i^2-2i/4i^2
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2iRationalise it again because we can't leave iota in denominator i+1/-2i × - 2i/-2i-2i^2-2i/4i^22-2i/-4
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2iRationalise it again because we can't leave iota in denominator i+1/-2i × - 2i/-2i-2i^2-2i/4i^22-2i/-41-i/-2
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2iRationalise it again because we can't leave iota in denominator i+1/-2i × - 2i/-2i-2i^2-2i/4i^22-2i/-41-i/-2-1/2 is real part
Answer:1-i/-2Step-by-step explanation:i/1-iRationalise it, i/1-i× 1-i/1-ii-i^2/1+i^2-2ii+1/1-1-2i ( as i^2=-1)i+1/-2iRationalise it again because we can't leave iota in denominator i+1/-2i × - 2i/-2i-2i^2-2i/4i^22-2i/-41-i/-2-1/2 is real part i/2 is an imaginary part