Question

Q.8.Find a cubic polynomial with zeroes as - ½ ,

2 and 2/3
​

Answer 1

Step-by-step explanation:

f(x)=2x

2

−3x

2

−3x+2

f(−1)=−2−3+3+2

f(−1)=0

As f−1=0

∴(x+1) is a factor of f(x)

f(x)=(x+1)(2x

2

−5x+2

f(x)=(x+1)(2x

2

−4x−−x+2)

f(x)=(x+1)(2x−1)(x−2)

f(x)=0

∴x=−1,

2

1

,2.