Question

Q.8 ) How can three resistors of resistance 2Ω, 3Ω and 6Ω be connected to give a total resistance of (a) 4Ω (b) 9Ω?​

Answer 1

Answer:

Hence, the total resistance of the circuit is 4 Ω. (b) To obtain a total resistance of 1Ω from three resistors of 2Ω, 3Ω and 6Q, all the three resistors should be connected in parallel. ⇒ 1/R = 1 Ω. Hence, the total resistance of the circuit is 1 Ω.

Explanation:

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