Question

Q.8.In a chemical reaction, 10.6 g of sodium carbonate reacted with 12 g of

ethanoic acid. The products obtained were 4.4 g of carbon dioxide, 16.4 g of

sodium ethanoate and 1.8 g of water.

(a) Write a word equation, clearly showing the reactants and products as given

above.

(b) Also show that this data is in agreement with the law of conservation of

mass​

Answer 1

Explanation:

Let the mass of sodium etanoate is “x”g Na2CO3 + CH3COOH → CH3COONa + CO2 + H2O 10.6g 12g xg 4.4g 1.8g Acoording to law of conservation of mass, Sum of masses of reactants = Sum of masses of products Hence, 10.6g +12.g = x + 4.4g +1.8g ⇒ x = 16.4g Thus, the mass of sodium ethanoate formed is 16.4gRead more on Sarthaks.com - https://www.sarthaks.com/946716/in-a-chemical-reaction-10-6-g-of-sodium-carbonate-reacted-with-12g-of-ethanoic-acid