Question

Q 8) In a triangle ABC, DE || BC. If AD
= x, DB = x - 2, AE = x + 2 and EC = x -
1, the value of x is:​

Answer 1

final value if x=4

and this is the ans

Answer 2

Given,DE//BC

$\frac{AD}{DB} = \frac{AE}{EC} \\ \\ \frac{x}{x -2 } = \frac{x + 2}{x - 1} \\ \\ x(x - 1) = (x + 2)(x - 2) \\ \\ {x}^{2} + x = {x}^{2} + 4 \\ \\ x = 4$