Q.8 In triangle PQR, angle Q =90°, PQ =12, QR =5 and QS is a median. find SQ = ...........
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PQ = 12, QR = 5 [Given]
In APQR, ∠Q = 90° [Given]
∴ PR2 = QR2 + PQ2 [Pythagoras theorem] = 25 + 144
∴ PR2 = 169
∴ PR = 13 units [Taking square root of both sides]
ii. In right angled APQR, seg QS is the median on hypotenuse PR.
∴ QS = (1/2) PR [In a right angled triangle, the length of the median on the hypotenuse is half the length of the hypotenuse]
= (1/2) x 13
∴ l(QS) = 6.5 units
#HAVE A NICE DAY
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