Q.8] Shown below are two cuboids , both cuboids have the same surface area , find 'y":
7cm
4cm
2 cm
1 cm
2cm
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Given : Two cuboids having same surface area
cuboid 1 : 7 cm by 4 cm by 2 cm
Cuboid 2 : y cm by 2 cm by 1 cm
To Find : Value of y
Solution:
Cuboid surface area = 2 ( lb + bh + lh )
Cuboid 1 surface area = 2 ( 7 * 4 + 4 * 2 + 7 * 2)
= 2( 28 + 8 + 14)
= 2( 50)
Cuboid 2 surface area = 2 ( y* 2 + 2 * 1 + y* 1)
= 2( 3y + 2 )
Equate both
2( 3y + 2 ) = 2( 50)
=> 3y + 2 = 50
=> 3y = 48
=> y = 16
Value of y is 16
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