Q. 8: Sides of triangles are given below. Determine which of them are right triangles.
In case of a right triangle, write the length of its hypotenuse.
(i) 7 cm, 24 cm, 25 cm
(ii) 3 cm, 8 cm, 6 cm
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Answers
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Answer:
Question:
Q. 8: Sides of triangles are given below. Determine which of them are right triangles.In case of a right triangle, write the length of its hypotenuse.(i) 7 cm, 24 cm, 25 cm(ii) 3 cm, 8 cm, 6 cm
Solution:
(i)
Given, sides of the triangle are 7 cm, 24 cm, and 25 cm.
Squaring the lengths of the sides of the, we will get 49, 576, and 625.
49 + 576 = 625
(7)2 + (24)2 = (25)2
Therefore, the above equation satisfies Pythagoras theorem. Hence, it is a right-angled triangle.
Length of Hypotenuse = 25 cm
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(ii)
Given, sides of the triangle are 3 cm, 8 cm, and 6 cm.
Squaring the lengths of these sides, we will get 9, 64, and 36.
Clearly, 9 + 36 ≠ 64
Or, 32 + 62 ≠ 82
Therefore, the sum of the squares of the lengths of two sides is not equal to the square of the length of the hypotenuse.
Hence, the given triangle does not satisfy Pythagoras theorem.
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Answer:-
i) perpendicular - 24cm
hypotenuse - 25cm
base- 7cm
H2 = P2 +B2
(25)2 = (24)2 + (7)2
625= 576+49
625=625
Therefore, it is a right triangle
ii) perpendicular - 6cm
hypotenuse - 8cm
base - 3cm
H2 = P2 + B2
(8)2= (6)2 + (3)2
64 = 36 + 9
64 is not equal to 45
Therefore, it is not a right triangle