Question

Q.8
The charge flowing through a conductor begining with time t = 0 is given by q=2t^2+3t+1(coloumbs).Find the current I =dq/dt at the end of the 5th second​

Answer 1

Answer:

I=dQ/dt = d(2t²+3t+1)/dt = 4t + 3 +0 = 4t+3

at time, t=5s

I= 4(5) + 3 = 20+3= 23 A

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Answer 2

Answer:

23 amp

Explanation:

given: q= 2t²+3t+1 & t=0. so, find in 5th second

differentiate the EQ.

4t+3+0=0

4t+3=0. ,put the value of t=5 in the EQ.

=4*5+3=0

=20+3=23 units =23 amp