Question

Q 8: The length of one of the diagonal of a quadrilateral is 10 cm. The perpendiculars drawn to it from the opposite vertices are of 2 cm and 6 cm respectively, then the area of this quadrilateral will be​

Answer 1

Answer:

area =

$\frac{1}{2} \times 10(2 + 6) \: \: \frac{1}{2}d(h1 + h2) \: \\ \\ > > > > > > > 5 \times 8 \: = \: \: 40 cm²\: \: \: ans$