Q.8 Which term is 0 of the AP 27, 24, 21, ....
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Answer:
Step-by-step explanation:
Let first term be a=27
And common difference be d=−3
According to question, sum is zero,
⟹ n \2 [2a+(n−1)d]=0
⟹[54+(n−1)(−3)]=0
⟹n=19
Hence, 19 terms of AP should be taken to make sum zero.
Value of the last term, i.e;
a 19 =a+(19−1)d
⟹a 19 =27+(18)(−3)
⟹a 19 =−27
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