Question

Q.8. Write the dimensions of a/b in the relation:
P=(a-t2)/bx
Where ‘P’ is the pressure, ‘ x’ is the distance and ‘t’ is the time

Answer 1

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Answer 2

Answer:

In the relationship, the dimensions of a/b are [ML⁰T⁻²].

Explanation:

The relation given in the question is,

$P=\frac{a-t^2}{bx}$   (1)

The unit for "a" will be the same as for "t²." Due to the fact that addition occurs only in equivalent numbers. So,

$a=[T^2]$     (2)

And "b" will be calculated as,

$b=\frac{a-t^2}{Px}$   (2)

For pressure(P),

$P=ML^-^1T^-^2$  (3)

Now equation (2) can be written as,

$b=\frac{[T^2]}{[ML^-^1T^-^2][L]}$

$b=[ML^0T^-^2]$      (4)

The dimension of "a divided by b" is therefore written as follows:

$\frac{a}{b} =\frac{[T^2]}{[ML^0T^-^2]}$

$\frac{a}{b} =[ML^0T^-^2]$

Hence, In the relationship, the dimensions of a/b are [ML⁰T⁻²].

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