Q 9 A battery of 9V is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 ohm, 0.5 ohm and 12 ohm. How much current flow through the 12 ohm resistor ?
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Total resistance of resistors when connected in series is given by
= 1 + 2 + 3 + 4 + 5
= 0.2 Ω+ 0.3 Ω+ 0.4 Ω+ 0.5 Ω+ 12 Ω = 13.4 Ω
According to Ohm’s law,
V = IR
I =V/R
I = 9 /13.4 = 0.67
▶▶There is no current division occurring in a series circuit.
So, the current through the 12 Ω resistor will be same as 0.67 A.
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