Question

Q.9 A man travels 300 km partly by train and partly by car. He takes 4
hours if the travels 60 km by train and the rest by car. If he travels 100 km
by train and the remaining by car, he takes 10 minutes longer. Find the
speeds of the train and the car separately.​

Answer 1

Answer:

11th

Physics

Motion in a Straight Line

Speed and Velocity

A man travels 300km party b...

PHYSICS

A man travels 300km party by train and partly by car. If the covers 60km by train and rest by car, it takes him 4 hours. If the travels 100km by train and rest by car, he takes 10 minutes longer. Find the speed of the train and the car.

MEDIUM

Share

Study later

ANSWER

Let, the speed of train be x & speed of bus be y.

Speed=

Time

Distance

or T=

S

D

4=

x

60

+

y

240

………….(1)

4 hr 10 min=

x

100

+

y

200

………..(2)

(1)×5

20=

x

300

+

y

240×S

(2)×3

62

25×3

=

x

300

+

y

600

20−

2

25

=

y

1200

−

y

600

2

15

=

y

600

y=80 km/ph

4=

x

60

+

80

240

x=60 km/ph.

it is answer of another question you may try to make that question from this steps

become follower

Answer 2

$\huge\bf\green{\mid{\fbox{\underline{\underline{Answer}}}}\mid}$

$\bf{https://brainly.in/question/37581179}$

Let the speed of train and bus be u km/h and v km/h respectively.

According to the question,

$\frac{60}{u} + \frac{240}{v} = 4$....(i)

$\frac{100}{u} + \frac{200}{v} = 4 + \frac{10}{60} = \frac{25}{6}$....(ii)

Let $\frac{1}{u} = p\: and \frac{1}{v} = q$

The given equations reduce to:

60p + 240q = 4 ....(iii)

100p + 200q = $\frac{25}{6}$

600p + 1200q = 25....(iv)

Multiplying equation (iii) by 10, we obtain:

600p + 2400q = 40....(v)

Subtracting equation (iv) from equation (v), we obtain:

1200q = 15

q = $\frac{15}{1200} = \frac{1}{80}$

Substituting the value of q in equation (iii), we obtain:

60p + 3 = 4

60p = 1

p = $\frac{1}{60}$

:. p = $\frac{1}{u} = \frac{1}{60}$, q = $\frac{1}{v} = \frac{1}{80}$

u = 60 km/h , v = 80 km/h

Thus, the speed of train and the speed of bus are 60 km/h and 80 km/h respectively.

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️