Question

Q.9 - A pole is broken at the height of 500cm from the footpath and its peak point is in
contact with the footpath at a distance of 1200cm from the base of the pole. Find the actual
length when it was in normal condition.​

Answer 1

Answer:

1800

Step-by-step explanation:

lets take P=500cm

and B=1200cm

so to find the length of pole we need to find the length of H,

by pythagoras theorem

H^2=B^2+P^2

H^2=(1200)^2+(500)^2

H^2=1440000+250000

H^2=1690000

H=1300

So the height of pole =P+H=500+1300=1800

Answer 2

Answer:

Its... 1800 cm.

Step-by-step explanation:

As it will form a right triangular figure with the base of 1200 cm, height of 500 cm and hypotenuse with the broken part of tree, we can apply the Pythagoras Theorem-

~ Hypo^2= 500^2 + 1200^2

Hypo = √1690000 cm

Hypo = 1300 cm

Thus, total height of the tree is ( 500 +1300)cm

gives us, 1800cm