Q 9. A sailor goes 8km downstream in 40 minutes and returns in 1hr. Determine the speed of the
sailor in still water & the speed of the current.
Ek sailor bahav ki disha me 8km jane ke liye 40min aur wapas aane ke liye 1 ghanta leta hai. To
sailor ki speed shaant pani me aur bahav ka speed kya hoga.?
(a) Speed of sailor - 10km/hr, speed of current - 2km/hr
(b) Speed of sailor - 15km/hr, speed of current - 3km/hr
(c) Speed of sailor - 20km/hr, speed of current - 4km/hr
(d) Speed of sailor - 16km/hr, speed of current - 4km/hr
Answers
Answered by
0
Explanation:
Let the speed of the sailor in still water be x km/hr and speed of the current be y km/hr.
Then, speed of sailor downstream =x+y km/hr and speed of sailor upstream =x−y km/hr.
Distance covered =8 km.
Also, Time=
Speed
Distance
From the given information, we have,
x+y
8
=
60
40
and
x−y
8
=1
or,
x+y
8
=
60
40
=>
x+y
8
=
3
2
=>24=2(x+y)
=>x+y=12....(i)
Also,
x−y
8
=1
=>x=8+y....(ii)
Substituting (ii) in (i), we get,
x+y=12
=>8+y+y=12
=>2y=4
=>y=2
Substituting y=2 in equation (ii), we get,
x=8+y
=>x=8+2
=>x=10
Therefore, speed of sailor in still water =x=10 km/hr
and speed of the current =y=2 km/hr.
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