Question

Q 9. A wire is bent into the form of a square of side 54 cm. The wire is straightened and bent into the form of a semi circle, then the radius of the semi circle so formed is​

Answer 1

Answer:

21

Step-by-step explanation:

so perimeter of the square = circumference of semi circle

4*54= (πr+2r)(since for semi circle we will have diameter attached to it )

r*(22/7+2)=4*54

r= 4*54*7/(22+14)

r=21