Question

Q.9.Factorise: (a²-b²)³+ (b-c²)³+(c2-a²)³​

Answer 1

hi .......

here is your answer....

Given (a²-b²)³+(b²-c²)³+(c²-a²)³=3(a+b)(b+c)(c+a)(a-b)(b-c)(c-a) Consider LHS:(a²-b²)³+(b²-c²)³+(c²-a²)³ We know that if x + y + z =0 then x3 + y3 + z3 = 3xyz Here x = a²-b², y = b²-c² and z = c²-a² a²-b² + b²-c² + c²-a² = 0 Hence (a²-b²)³+(b²-c²)³+(c²-a²)³ = 3(a²-b²)(b²-c²)(c²-a²)³ = 3(a + b)(a − b)(b + c)(b − c)(c + a)(c − a) = 3(a + b)(b + c)(c + a)(a − b)(b − c)(c − a)

hope that it help u more

Answer 2

Answer:

I also have same question