Question

Q:-9) Find the particular solution
of the differential equation
Cos3 ydx + xCosydy - Sinydy, given
that x=1, y=0

​

Answer 1

Answer:

Hamen Nahin Aata Khud kar le bhai

Answer 2

Answer:

cosydy+cosxsinydx=0

⇒+cotydy=−cosxdx

Now integrating, we get

lnsiny=−sinx+C

⇒lnsiny+sinx=C

Put x=

2

z

and y=

2

z

, we get

lnsin

2

z

+sin

2

z

=C

ln(1)+1=C

C=1

Equation is

lnsiny+sinx=1