Q.9. If length of a diagoanl of
flength of a diagoanl of a rhombus is 30 cm and its area is 240 sq.cm., find its perimeter.
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the answer of your question is this
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Step-by-step explanation:
d1*d2/2 = area of rhombus
Since diagonals of a rhombus bisect each other at 90 degree , therefore half of side = 15
by formula of area
d2 = 16 CM by Pythagoras theorem side of rhombus = 17cm
perimeter of rhombus = 17*4 = 68 cm^2
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